| Sphere-Plane | Cylinder-Plane | |
| Contact Diameter/Width | b = 1.44·[DCEF]1/3 | b = 1.60·[DCEF/L]1/2 |
| Contact Area | A = πb2/4 | A = b·L |
| Deformation | x = 0.5·(b2/D) | x = 0.124·(b2/D)·ln(2.791·D/b) |
| Maximum Stress | σ = 1.5·F/A | σ = 1.277·F/A |
| Load Limit | Fmax = (σy/0.918)3(D2CE2) | Fmax = (σy/0.798)2(LDCE) |
The top part of the interface consists of a contact line between a sphere and a cone, which is equivalent to a cylinder-plane contact line with length Lcone, and contact diameter D.
The bottom part of the interface consists of two cylinder-plane contact lines, with a total length of 2L or 2kLD, and contact diameter D. To equate the cylinder contact line with the cone, we define:
The maximum allowed vertical force F, as determined by each of the contact line interfaces is:
In the case of the sphere, the two sphere-to-groove contacts are always the weak point, and so a wider-angle V-groove can carry more load, though this comes at the expense of weaker centering forces.
In the case of the Spherolinder, the weak spot is eliminated, and the load capacity of both interfaces can be equated by controlling the combination of L and θv.
For θv = θc = 90°,
This is short enough that in our product line, we opted to keep the V-groove at 90° rather than make L = D by making the V-groove shallower. All of our mounting blocks, therefore, have right-angle features.
Since the contact area is a variable, the rigidity is not constant (the system is not linear), and so we want to calculate two rigidity figures:
Using the same geometry, the cone or v-groove angle amplifies the normal deformation by the same factor it has magnified the force by. (If the system was linear, it would have resulted in an overall
And since xcone = xcylinder, xsphere >> xcylinder, and θv=θc
For the sphere, KDC ≈ F/(xsphere/sin(θv/2)
For the Spherolinder, KDC = F/(2·xcone/sin(θc/2))
For either case, KAC = dF/dx = 1/(dx/dF).
The above calculations are for a single mounting site - a complete mount contains 3 mounting sites, so the load has to be adjusted accordingly. For a horizontal symmetrical application, the load is evenly distributed, and only a third of it acts on each mounting site. To carry out these calculations, please use our web calculator.